if tan theta,=1/2tan fii =1/3then the value of thita+ fii
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tan(theta+dii)=(tan theta+tan fi)/(1-tan theta.tan fii)
=(1/2+1/3)/(1-1/2.1/3)
=(5/6)/(1-1/6)
=5/6.6/5
=1
hence, (theta+fii)= π/4
=(1/2+1/3)/(1-1/2.1/3)
=(5/6)/(1-1/6)
=5/6.6/5
=1
hence, (theta+fii)= π/4
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