If tan theta =1/√3 find the value of sin theta +cos theta /sin theta - cos theta
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Tan theta=4/3
tan theta=p/b
p=4,and b=3
by paithagoras theorem,
H=root under P^2+B^2
H=root under 4^2+3^2
H=root under 16+9
H=root under 25
H=5
sin theta=p/h
sin theta=4/5
cos theta=b/h
cos theta=3/5
sin theta+cos theta/sin theta-cos theta
=4/5+3/5 by 4/5-3/5
=4+3/5by4-3/5
=7/5by1/5
=7/5×5/1
=7/1
=7
hope it will help you.
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