if tan theta = 1 /√3 , then evaluate
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HELLO SWEETU !!!
tan²x + 1 = sec²x
1/3 + 1 = sec²x
sec²x = 4/3
cot²x + 1 = cosec²x
cosec²x=4
substitute in the equation above...
=[4 - 4/3]/[4 + 4/3]
= 8/3 * 3/16
=1/2
HOPE IT HELPS......
LUV U ❤❤
tan²x + 1 = sec²x
1/3 + 1 = sec²x
sec²x = 4/3
cot²x + 1 = cosec²x
cosec²x=4
substitute in the equation above...
=[4 - 4/3]/[4 + 4/3]
= 8/3 * 3/16
=1/2
HOPE IT HELPS......
LUV U ❤❤
yana85:
thanx baby
Answered by
4
HOLA MATE !!!
HOPE THIS HELPS YOU...
To find :-
[cosec²x - sec²x] / [cosec²x + sec²x] = ?
Answer:
We know that,
=> tan²x + 1 = sec²x
then putting the values,
=> 1/3 + 1 = sec²x
=> sec²x = 4/3
and also,
=> cot²x + 1 = cosec²x
=> cosec²x=4
Step-by-step Explanation:-
Substitution and simplification in the above given equation.
=[cosec²x - sec²x] / [cosec²x + sec²x]
=[4 - 4/3]/[4 + 4/3]
= 8/3 * 3/16
=1/2
Hence,the value of above given equation is 1/2.
THANK YOU FOR THE WONDERFUL QUESTION...
#bebrainly
HOPE THIS HELPS YOU...
To find :-
[cosec²x - sec²x] / [cosec²x + sec²x] = ?
Answer:
We know that,
=> tan²x + 1 = sec²x
then putting the values,
=> 1/3 + 1 = sec²x
=> sec²x = 4/3
and also,
=> cot²x + 1 = cosec²x
=> cosec²x=4
Step-by-step Explanation:-
Substitution and simplification in the above given equation.
=[cosec²x - sec²x] / [cosec²x + sec²x]
=[4 - 4/3]/[4 + 4/3]
= 8/3 * 3/16
=1/2
Hence,the value of above given equation is 1/2.
THANK YOU FOR THE WONDERFUL QUESTION...
#bebrainly
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