if tan theta =1/√3,then the value of 2theta=
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0
Answer:
SORRY IM NOT EXPERCT IN THAT
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Answered by
2
Answer:
tanθ=
3
1
⇒tanθ=tan30
∘
⇒θ=30
∘
cosec
2
θ+sec
2
θ
cosec
2
θ−sec
2
θ
=
cosec
2
30
∘
+sec
2
30
∘
cosec
2
30
∘
−sec
2
30
∘
=
2
2
+(2/
3
)
2
2
2
−(2/
3
)
2
=
4+4/3
4−4/3
=
12+4
12−4
=
16
8
=
2
1
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