Question

If tan theta = 1/√3 then find sin ^ 2 theta - cos ^ 2/theta

Answer 1

Find the value:

Step-by-step explanation:

In the given expression there is a typing mistake So, the correct equation to this question can be defined as follows:

$\ Given \ equation:\\\\\tan \theta = \frac{1}{\sqrt{3}}\\\\\ Find:\\\\\sin^2\theta-\cos^2\theta = ?\\\\\ Solution:\\\\\tan \theta = \frac{1}{\sqrt{3}}\\\\\rightarrow \tan \theta = \tan 30^\circ\\\\\rightarrow \theta = 30^\circ\\\\\sin^2\theta-\cos^2\theta = ?\\\\\rightarrow \sin^2 30^\circ-\cos^2 30^\circ \\\\\rightarrow ((\frac{1}{2})^2-(\frac{\sqrt{3}}{{2}})^2)\\\\\rightarrow (\frac{1}{4}-\frac{3}{{4}})\\\\\rightarrow (\frac{1-3}{4})\\\\\rightarrow \frac{-2}{4}\\\\\rightarrow -\frac{1}{2}$

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