If tan theta =1/root 3 , then find the value of (4 cos ^2 theta - 3)/(3 sin ^2 theta + 1) .
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Answer:
tan theta =1/root 3
tan theta =tan30 degree
theta = 30 degree
So,
(4 cos ^2 theta - 3)/(3 sin ^2 theta + 1)
(4 cos ^2 30degree - 3)/(3 sin ^2 30degree + 1)
(4 (root3/2)² - 3)/(3 (1/2²) + 1)
(4×3/4 - 3)/(3×1/4 + 1)
(3/4 - 3)/(3/4 + 1)
(3-12/4)/(3+4/4)
(-9/4)/(7/4)
-9/7 -----------------(Answer)
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