Question

If tan theta= 1/root3, prove that 7 sin^2 theta + 3 cos^2 theta = 4

Answer 1

Answer:

7sin²θ + 3cos²θ = 4

7sin²θ + ౩(1-sin²θ) = 4

7sin²θ+3-3sin²θ = 4

4sin²θ+3 = 4

4sin²θ=1

sin²θ = 1/4

sinθ = +1/2

sinθ = +  π/6

Therefore tan θ = + π/6

then we get tan θ = + 1/√3