Question

if tan theta=1 then 7sin²theta +3cos²theta =​

Answer 1

Answer:

4sin

2

θ+3(sin

2

θ+cos

2

θ)=4

4sin

2

θ+3=4

4sin

2

θ=1⇒sinθ=

2

1

AC

2

=AB

2

+BC

2

4−1=AB⇒AB=

3

tanθ=

BA

BC

=

3

1

Step-by-step explanation:

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Answer 2

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