if tan theta = 1, then find the values of sin theta+cos theta/sec theta+cosec theta
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the correct of
the question
is
1/2
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Answer:
tanQ = 1
so, we can say 1 = tan45°
so, tanQ = tan45°
so, Q = 45°
(sinQ + cosQ)/ (secQ + CosecQ)
(sinQ+cosQ) ÷ (secQ+ cosecQ)
(sinQ+cosQ) ÷ ( 1 / cosQ + 1/ SinQ)
(sinQ+cosQ) ÷ (cosQ+sinQ)/CosQSinQ
(SinQ+CosQ) × cosQsinQ/(cosQ + sinQ)
==> CosQsinQ
we know that Q = 45°
==> Cos45° × Sin45°
==> ( 1/√2 × 1/√2)
==> 1/2
answer = 1/2
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