Math, asked by anilchavan3845, 11 months ago

If tan theta = 1 upon 2√2 then find the value of cos square theta

Answers

Answered by Anonymous
0

Step-by-step explanation:

sec^2teta-tan ^2teta=1

sec^2teta=1+tan^2teta

=1+(1/2× root2)^2

=1+1/8

=8+1/8

sec^2teta =9/8

but sec^2teta=1/cos^2teta

cos^2teta=1/sec^2teta

=8/9.

Similar questions