If tan theta =12/5 then 5sin theta- 12 costheta.
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tan theta = 12 / 5 = p/ b ; sin theta = 12 /5
Now;
cos theta = b/ h
therefore cos theta = b/ h = 5 / 5 = 1
Now;
cos theta = b/ h
therefore cos theta = b/ h = 5 / 5 = 1
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