Question

If tan theta
=12/5
then find the value of 1+cos theta/ 1-cos theta

​

Answer 1

$\huge\fcolorbox{red}{cyan}{25}$

Step-by-step explanation:

• Tan Theta = 12/5

$\tan( \theta) = \frac{perpendicular}{base}$

Therefore :-

• Perpendicular = 12

• Base = 5

Now Lets Caculate The Hypotenuse :-

By Pythagorus Theoram :-

$h \: = \sqrt{p {}^{2} + {b}^{2} } \\ = > h = \sqrt{1 {2}^{2} + {5}^{2} } \\ = > h = \sqrt{144 + 25} \\ = > h = \sqrt{169} \\ = > h = 13$

Thus Hypotenuse is 13

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Now :-

$\cos( \theta) = \frac{base}{hypotenuse} \\ = > \frac{5}{13}$

Now As per question :-

$\frac{1 + \cos( \theta) }{1 - cos( \theta)} \\ = > \frac{1 + \frac{base}{hypotenuse} }{1 - \frac{base}{hypotenuse} } \\ = > \bf{lets \: put \: the \: values} \\ = > \frac{1 + \frac{5}{13} }{1 - \frac{5}{13} } \\ \\ = > \frac{ \frac{13 + 5}{13} }{ \frac{13 - 5}{13} } \\ \\ = > \frac{ \frac{18}{13} }{ \frac{8}{13} } \\ \\ = > \frac{18}{8} \\ = > \boxed{\frac{9}{4}}$

Hope it helped

Answer 2

Answer:

25

Step-by-step explanation:

is the correct answer of this question