if tan theta = 16/63 then find sin theta and cos theta
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If tan A = 16/63, it means the side opposite to <A = 16 and the side adjacent to <A = 63. The hypotenuse = (16^2+63^2)^0.5 = [256+3969]^0.5 = 4225^0.5 = 65.
Now sin 2A = 2 sin A cos A = 2*(16/65)*(63/65) = 2016/4225 = 0.477159763.
Check: With a calculator A = arctan (16/63) = 14.2500327 deg.
So 2A = 2*14.2500327 = 28.5000654 deg
sin 28.5000654 = 0.477159763. Correct.
sin 2A = 0.477159763.
Step-by-step explanation:
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