If (tan theta + 2)(2 tan theta + 1) = A tan theta + B sec² theta, then AB
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Answer:
Solution:-. Given that: (tan θ+ 2)(2 tan ...
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Step-by-step explanation:
Given :-
2x² - 4x + 5
To Find :-
1/α + 1/β
(α - β)²
Solution :-
We know that
Sum of zeroes = -b/a
Here
b = -4
a = 2
-(-4)/2
4/2
2/1
2
Product of zeroes = c/a
c = 5
a = 2
5/2
Now
1/α + 1/β = α + β/αβ
= 2/(5/2)
= 2/5 × 2/1
= 4/5
b)
We know that
(α - β)² = (α + β)² - 4αβ
(2)² - 4(5/2)
4 - 20/2
8 - 20/2
-12/2
-6
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