If tan(theta/2)=5/2 and tan(phi/2)=3/4 then find value of cos(theta+phi)
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Given,
Tan (θ/2) = 5/2;
Tan (ϕ/2) = 3/4;
Now,
We know that, Tan (A+B) = (Tan A + Tan B) / (1 + Tan A x Tan B);
So,
Tan (θ/2 + ϕ/2) = (Tan θ/2 + Tan ϕ/2 ) / (1 + (Tan θ/2 x Tan ϕ/2) );
Tan (θ/2 + ϕ/2) = (5/2 + 3/4) / (1 + (5/2 x 3/4) );
Tan (θ/2 + ϕ/2) = (13/4) / (1 + 15/8);
Tan (θ/2 + ϕ/2) = (13/4) / (23/8);
Tan (θ/2 + ϕ/2) = 26/23;
(θ/2 + ϕ/2) = Tan-1(26/23);
Θ + ϕ = 2 Tan-1(26/23);
So,
Cos (Θ + ϕ) = Cos (2 Tan-1(26/23) );
Sameerabhi:
it's wrong...
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