if tan theta =2 x/3 y show that sec^2-tan^2=1
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Answer:
tanθ=
1−e
2
→secθ+tan
3
θ cosecθ
→
cos
3
θ
cos
2
θ+sin
2
θ
→sec
3
θ
→(secθ)
3
→(
1+tan
2
θ
)
3
→(1+1−e
2
)
3/2
→(2−e
2
)
3/2
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