If tan theta = 2ab / a2-b2 then find all other trigonometric ratios
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Step-by-step explanation:
tan theta = perpendicular/base
= 2ab/ (a²-b²)
perpendicular : base: hypotenus
= 2ab : (a²-b²) : √[(a⁴+b⁴-2a²b²)+4a²b²]
= 2ab : (a²-b²) : ( a²+b²)
= P : B :. H
thus,. sinA= P/H= (2ab / ( a²+b²)
cosA= B/H = (a²-b2) / (a2+b2)
cotA. = B/P= (a²- b2) / 2ab
secA= H/B= (a2+b2) / (a2-b²)
cosecA= H/P= (a2+b²) / 2ab
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