If tan theta = 2ab/ a2 - b2 , then find all other trigonometric ratios .
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It is given that tan @=2ab/a²-b²
By using pythagoras theorm we can find that hypotenuse is
a²+b².
Then, sin @ = perpendicular / hypotenuse
= 2ab/a²+b²
cos@ = base / hypotenuse
= a²-b²/a²+b²
cosec@ = 1/sin@ = a²+b²/2ab
sec@ = 1/cos@ = a²+b²/a²-b²
cot@ = 1/tan@ = a²-b²/2ab
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