If tan theta=3/4 calculate 3sintheta+2cos theta/ 3sin theta -2cos theta
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tan theta =3/4=P/B
Where P stands for perpendicular & B stands for Base &H is Hypotenuse
By using pythagorus theorem we get
H=5
NOW
(3 Sin theta + 2 Cos theta )/(3 Sin theta -2 Cos theta )=((3×3/5)+(2×4/5))/((3×3/5)-(2×4/5)
= (9/5+8/5)/(9/5 -8/5)
=(17/5)/(1/5)
=17 Answer
I hope it will be able to understand
Where P stands for perpendicular & B stands for Base &H is Hypotenuse
By using pythagorus theorem we get
H=5
NOW
(3 Sin theta + 2 Cos theta )/(3 Sin theta -2 Cos theta )=((3×3/5)+(2×4/5))/((3×3/5)-(2×4/5)
= (9/5+8/5)/(9/5 -8/5)
=(17/5)/(1/5)
=17 Answer
I hope it will be able to understand
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