Question

if tan theta=3/4, then find the value of sin theta and sec theta


​

Answer 1

Step-by-step explanation:

hope this is helpful.......

Answer 2

Answer:

$[tex] tan\theta = \frac{3}{4}\\\\ As\ we\ know:-\ tan\theta = \frac{P}{B}\\\\ \therefore P=3\ and\ B=4\\\\ For\ finding\ the\ H:-\\\\ H^{2}=B^{2}+P^{2}\\\\ H^{2}=9+16\\\\ H=\sqrt{25}\ \implies H=5\\\\ \therefore sin\theta = \frac{P}{H} = \frac{3}{5}\\\\ and\ sec\theta= \frac{H}{B} = 5/4$

Step-by-step explanation:

Hope it helps you buddy :)