if tan theta = 3/4 then sec²A-tan²A
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Explanation:
because we know sec²a-tan²a=1
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- sec²A - tan²A = 1
Proof :-
- tan θ = 3/4 = opposite / adjacent = height / altitude
- hypotenuse = √(3)²+(4)² = √9+16 = √25 = 5
- sec θ = hypotenuse/adjacent = 5/4
- sec² A - tan² A = (5/4)² - (3/4)²
- = (25/16) - (9/16) = (25-9)/16 = 16/16 = 1
- sec² A - tan² A = 1
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