Question

if tan theta =√3 evaluate (1-cos ^2 theta /1+cos^2 theta)​

Answer 1

This is the answer

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Answer 2

Answer:

3/5

Step-by-step explanation:

1.       tan θ =√3  

     tan θ = tan 60

      θ  = 60

2.  (1-cos²θ  /1+cos²θ )​

  (1- cos² 60) / 1 +cos² 60)

  (sin ² 60) / 1 +cos² 60)

  ( √3/2 )² / {1 + (1/2)²}

   $\frac{3}{4}$ / 1 + $\frac{1}{4}$

   $\frac{3}{4}$ / $\frac{4+1}{4}$

    $\frac{3}{5}$  { 4 and 4 get cancels and 4+ 1 = 5}

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