Question

if tan theta =√3, than find the values of sin ^2 theta -cos^2 theta, where theta is acute angle​

Answer 1

Step-by-step explanation:

thetha = A

tanA=root 3=tan60

A=60

sin^2A= sin^2 60 =( root3/2)=3/4

-cos^2A= -cos^2 60 = (1/2)^2 =1/4

Answer 2

Answer:

tanθ=√3

tanθ=tan60      

⇒θ=60

sin²60-cos²60

(sin60+cos60)(sin60-cos60)

(√3/2 + 1/2)(√3/2-1/2)

(√3+1/2)(√3-1/2)

(√3)²-1²/2*2

3-1/4

2/4

1/2

Step-by-step explanation: