Question

if tan theta = 3, then 5[cos theta/4] =

please explain ​

Answer 1

Given,
5tanθ=3
∴tanθ=
5
3
​

Now,
4sinθ+3cosθ
5sinθ−3cosθ
​


=
4tanθ+3
5tanθ−3
​
[dividing numerators and denominator by cosθ]

=
4(
5
3
​
)+3
5(
5
3
​
)−3
​


=
5
12
​
+3
3−3
​


=
5
12
​
+3
0
​


=0

∴
4sinθ+3cosθ
5sinθ−3cosθ
​
=0

Answer 2

tan theta =3 /1

9+1=s^2

s=√10

cos theta=1/ √10

5[1/√10/5]=5[1/√10* 1/4]

=5[1/4√10]

=5/4√10