Math, asked by chaya67, 3 months ago

if tan theta =√3 then sec theta = pls explain how the ans came​

Answers

Answered by kroy77259
0

Answer:

27

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Answered by verdanish63
0

Answer:

 {tan}^{2}x + 1 =  {sec}^{2}x \: \\  is \: the \: formula. \:  \\ so \: if \: tanx =  \frac{ \sqrt{3} }{1}  \: then \\  {tan}^{2}x  =  { \sqrt{3} }^{2}  = 3 \\ and \:  {tan}^{2}x + 1 = 3 + 1 = 4. \\ but \:  {tan}^{2}x + 1 =  {sec}^{2}x \\ i.e. \:  \:  \:  {sec}^{2}x \:  = 4 \\ sec(x) =  \sqrt{4}  \\ sec(x) = 2

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