If tan theta = -5\12, evaluate sin theta-cos theta\sin theta + cos theta
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tanθ= perpendicular/base
we are given that tanθ= -5/12
on Comparing
p=5
b=12
by p. g. t
H
h^2= 5^2++12^2
h^2=√5^2+12^2
h^2=√25+144
h^2=√169
h^2=√13×13
h^2=13
sin theta=p/h=5/13
cos theta=b/h=12/13
so, sin theta +cos theta/ sin theta-cos theta
12/13+5/13/12/13-5/13=17/7
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