if tan theta =5/12 then find sin^2 theta+COS^2 theta
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Answer:
if tan A = 5/12
opposite side of A = 5
adjacent side = 12
hypotenuse = √5²+12²= √25+144= √169= 13
sin²A+ cos²A = (5/13)² + ( 12/13)²
sin²A+ cos²A= 25/169 + 144/169
sin²A+ cos²A= 25+144/169
sin²A+ cos²A= 169/169
sin²A+ cos²A= 1
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