if tan theta =a/b find the value of sec theta
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tan theta =. a/b
height/base= a/ b
therefore, height= a
base= b
by Pythagoras theorem
hypotenuse square = sum of square of other sides
let hypotenuse be " c"
c square = a square+ b square
therefore, c=the whole square root of a square +b square
sec theta = hypotenuse/base
= the whole square root of a square +b square/ b
height/base= a/ b
therefore, height= a
base= b
by Pythagoras theorem
hypotenuse square = sum of square of other sides
let hypotenuse be " c"
c square = a square+ b square
therefore, c=the whole square root of a square +b square
sec theta = hypotenuse/base
= the whole square root of a square +b square/ b
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29
this is correct answer plz. mark as brainlest
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