If tan theta = a/b
sin theta+cos theta /sin theta - cos theta = ?
please explain step by step
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Answer:
a+b/a-b
Step-by-step explanation:
tan theta=opposite/base, with the help of pythagoras we got,
hypotenuse =a^2+b^2
base=b
opposite=a
sin theta=a/a^2+b^2
cos theta=b/a^2+b^2
sin theta+cos theta/ sin theta- cos theta =
(a/a^2+b^2 + b/a^2+b^2) / a/a^2+b^2 - b/a^2+b^2
taking l.c.m. we got
=(a+b/a^2+b^2) / a-b/a^2+b^2
a^2+b^2 be cut we got =a+b/a-b
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