Question

if tan theta + cot theta = 2 then find tan 9 theta + cot 9 theta

Answer 1

Answer:

tan theta +cot theta=2

Step-by-step explanation:

tan +1/tan =2 [cot=1/tan]. [taking lcm]

${tan}^{2} + 1 \div tan = 2$

tan^2 +1=2tan

tan^2-2tan+1=0

${(tan - 1)}^{2} = 0$

tan-1=0

tan=1

cot=1/tan

cot=1/1

cot=1

${tan}^{9} + {cot}^{9} =$

(1)^9+(1)^9. {tan=1}. {cot=1}

1+1=2

than your answer is 2

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