Question

if tan theta+cot theta=6,then what is the value of tan^2 theta +cor^2 theta

Answer 1

Answer:

34

Step-by-step explanation:

tanθ +cot θ = 6

squaring on both sides

(tanθ +cot θ)² = (6)²        [ (tanθ +cot θ)² is in the form (a+b)²= a²+b²+2ab]

tan²θ + cot²θ + 2tanθcot θ = 36            [cot θ= 1/tanθ]

tan²θ + cot²θ + 2tanθ1/tanθ = 36            [tanθ gets cancelled]

tan²θ + cot²θ + 2 = 36    

tan²θ + cot²θ = 36 - 2

tan²θ + cot²θ = 34