if tan theta + cot theta is equals to 2 then 10 square theta + cot square theta is equals to?
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Well, the correct question is to find the value of tan²θ + cot²θ. So,
(tanθ + cotθ)² = 2²
tan²θ + cot²θ + 2 · tanθ · cotθ = 4
tan²θ + cot²θ + 2 = 4 [because cotθ = 1/tanθ]
tan²θ + cot²θ = 2
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tan^2 theta +cot^2 theta = 2
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