If tan theta equal to 1 the value of 5sintheta+4costheta /5sintheta-
4costheta
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here tanθ=1
now 5sinθ +4cosθ/ 5sinθ- 4cosθ
=(5sinθ/cosθ +4)/(5sinθ /cosθ -4)(dividing numerator and denominator by cosθ)
=(5tanθ+ 4)/(5tanθ-4)
=(5×1+4)/(5×1-4)
=(5+4)/1
=9/1
=9
now 5sinθ +4cosθ/ 5sinθ- 4cosθ
=(5sinθ/cosθ +4)/(5sinθ /cosθ -4)(dividing numerator and denominator by cosθ)
=(5tanθ+ 4)/(5tanθ-4)
=(5×1+4)/(5×1-4)
=(5+4)/1
=9/1
=9
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