Math, asked by raghav447394, 11 months ago

if tan theta equals to 1 by root 3 then find the value of 2 tan theta upon 1 minus 10 squared theta​

Answers

Answered by whitedevil00739
2

Answer:

2 ×1/root 3/1- (1/root 3) ^2

2/root3/1-1/3

2/root3/2/3

2/root3×3/2

root3×root3/root 3

=root 3

=tan60

Answered by ChiKesselman
0

The value of given expression is √3.

Step-by-step explanation:

We are given the following in the question:

\tan \theta = \dfrac{1}{\sqrt3}

We have to find the value of the expression:

\dfrac{2\tan \theta}{1 - \tan^2 \theta}

Putting the given value, we get,

=\dfrac{2(\frac{1}{\sqrt3})}{1 - (\frac{1}{\sqrt3})^2}\\\\=\dfrac{\frac{2}{\sqrt3}}{1-\frac{1}{3}}\\\\=\dfrac{\frac{2}{\sqrt3}}{\frac{2}{3}}\\\\= \sqrt{3}

Thus, the value of given expression is √3.

#LearnMore

If tan theta + 1/tan theta = 2 then show that tan^2 theta + 1/tan^2 theta = 2.

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