if tan theta equals to 12 by 13 find the value of 2 sin theta × cos theta by cos square theta minus sin square theta
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p/b=12/13
h=√313
2 sin theta * cos theta/cos sq theta - sin sq theta
2*p/h * b/h by 1-sin sq. theta-sin sq.theta
2*12/√313*13/√313 by
1- 2 * 12 sq./√313 sq.
312/313 by 1- 2*144/313
312/313-288
312/25
h=√313
2 sin theta * cos theta/cos sq theta - sin sq theta
2*p/h * b/h by 1-sin sq. theta-sin sq.theta
2*12/√313*13/√313 by
1- 2 * 12 sq./√313 sq.
312/313 by 1- 2*144/313
312/313-288
312/25
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92
hope this may help you in board exams
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