Math, asked by karamjit5911kot, 9 months ago

If tan theta is 1/√5 evaluate cosec^2-sec^2/cosec^2+sec^2

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Answered by sweetyheree
1

Answer:

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Answered by Anonymous
0

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Tan theta^2 = 1/5

sec^2 theta - 1 = 1/5

sec^2 theta = 6/5

Now,

reciprocal tan theta and squaring we get,

cot theta^2 = 5

cosec^3 theta - 1 = 5

cosec^2 theta = 6

now putting value in the que we get ans = 2/3

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