Question

if tan theta is equal to 3 by 4 then 7 sin theta minus 3 cos theta upon sin theta + 2 cos theta is equal to
$\tan( \alpha ) = \frac{3}{4} then \: \frac{7 \sin( \alpha ) - 3 \cos( \alpha ) }{ \sin( \alpha ) + 2 \cos( \alpha ) }$

Answer 1

Tan∅ = 3/4 = l/b

=> L = 3 and b = 4

H² = (b² + l²)

=> H² = (16 + 9)

=> H² = 25

=> H = 5

Sin∅ = 3/5

Cos∅ = 4/5

(7sin∅ - 3cos∅)/(sin∅ + 2cos∅)

=> ( 7×3/5 - 3×4/5) / (3/5 + 2×4/5)

=> (21/5 - 12/5) / ( 3/5 + 8/5)

=> {(21-12)/5) / {(3+8)/5}

=> 9/5/11/5

=> 9/11