if tan theta is equal to x/y find cos theta - sin theta / cos theta + sin theta
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When value of tanA is given say m/n,
you've : m/n = y/x.
So, y= mk & x = nk.
r = (x^2 + y^2)^1/2.
r = [ (mk)^2 + (nk)^2 ]^1/2
r = [ k^2(m^2+n^2) ]^1/2
r = k (m^2+n^2)^1/2
sinA = y/r = mk/k(m^2+n^2)^1/2
= m/(m^2+n^2)^1/2
Similarly, cosA = n/(m^2+n^2)^1/2.
Example -
tanA = 4/3
So, y= 4k & x = 3k.
r = (16k^2 + 9k^2 )^1/2 = + -5k.
sinA = + - 4/5 & cosA = + - 3/5.
Method 2 -
I explain it directly with an example.
tanA = 3/4.
sec^2A = 1 + tan^2A = 1+9/16=25/16.
secA = + - 5/4 so cosA = + - 4/5.
sinA = tanA*cosA = + - 3/5.
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