Question

if tan theta=root 3 then find the value of (2 sec theta/1+tan²theta)​

Answer 1

Answer:

Answer = 1

Step-by-step explanation:

Tan theeta = root 3

tan 60 = root 3

substitute value of theeta (60)

substitute value of theeta (60)in the given equation

=>(2× sec theeta)/1+tan^2 theeta

=>(2× sec theeta)/1+tan^2 theeta 1+tan ^2 theeta = sec^2 theeta

=>(2× sec theeta)/1+tan^2 theeta 1+tan ^2 theeta = sec^2 theeta => (2×sec theeta) /sec ^2 theeta

2 theeta = (2× sec 60)/sec ^2 60

sec 60 = 2

(2×2)/2^2 =4/4

= 1