Question

if tan theta +sec theta =1•5 then find sin theta and cos theta

Answer 1

tanθ+secθ
= (sinθ+1)/cosθ =3/2
Let sinθ=3k-1
cosθ=2k

We know, sin²θ +cos²θ =1
Substituting, we get,
(3k-1)²+(2k)²=1

Solving, we get,
k= 0 or 6/13
But k cannot be 0
so k=6/13

:. sinθ= 5/13
cosθ= 12/13

Hope this helps!!!!☺️