if tan theta + sin theta equals to M and tan theta minus sin theta equals to N in show that M²-N² =4√mn
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Solution is in the attachment
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Let that theta=$
then
tan$+sin$=M
tan$-sin$=N
M^2-N^2=(tan$+sin$)^2-(tan$-sin$)^2
=4tan$sin$.
what is m and n is not detailed here so it can be done to this.
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