Question

if tan theta +sin theta=m and tan theta -sin theta =n then m2-n2)2​

Answer 1

Answer:

LHS :

(m

2

−n

2

)=(tanθ+sinθ)

2

−(tanθ−sinθ)

2

=4tanθsinθ

RHS :

4

mn

=4

(tanθ+sinθ)(tanθ−sinθ)

=4

tan

2

θ−sin

2

θ

=4

cos

2

θ

sin

2

θ

−sin

2

θ

=

cosθ

4sinθ

1−cos

2

θ

=4tanθsinθ

Thus, LHS = RHS

Hence, m

2

−n

2

=4

mn