If tan thetha = 1/ root 7. Find sinQ +cosQ
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tan Theta=1/√7
tan Theta= perpendicular/base or,p/b
therefore, p=1 and b=√7
by applying Pythagoras theorum,
h^2=p^2+b^2
h^2=1^2+(√7)^2
h=√1+7
h=√8
sin Theta =p/h=1/√8
cos Theta=b/h=√7/√8
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