If tan thetha =√3 find value of sin thetha cos thetha
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Tan theta=√3
or,p/b=√3
So, P=√3 and b=1
Now, using pythagoras theorem,
h^2=p^2+b^2
or,h=2
Then, sin theta=p/h=√3/2
And, cos theta =b/h=1/2
pz mark my answer the brainliest....
Or, u can also do this in the given way,
Tan theta= √3
or, tan theta= tan 60 degree
Theta=60 degree
So, sin theta= sin 60 degree= √3/2
And, cos theta= cos 60 degree= 1/2
Pz mark.my answer the bdainliest
Sanaidrishi1804:
Prove that : tan theta -cot thetha/ sin theta cos there's =tan^2-cot^2 theta
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