Question

. If tan thita=1/√3 then the value of costhita is​

Answer 1

Answer:

Step-by-step explanation:

tan∅= 1/√3

tan∅= perpendicular/base=1/√3

∴cos∅= base/hypotenuse

By pythagoras theorem;

hypotenuse² = base² + perpendicular²

h²=(√3)² + 1

h²= 3+1

h²=4

∵h=2

∴cos∅=√3/2

Answer 2

Answer:

cos theta = √3/2

Step-by-step explanation:

tan theta = 1/√3

But tan theta = Perpendicular / Base

THERFORE, perpendicular /Base = 1/√3

AC² = AB²+BC² (by Pythagoras theorem)

AC² = (1)² +(√3)²

AC² = 1 + 3

AC = √4

THERFORE AC = 2

cos theta = BASE/HYPOTENEUS

THERFORE COS THETA = √3/2