Question

If tan thita=3/4, find the values of sec and cos thita

Answer 1

Tan x =3/4
using the identity
${ \sec( x) }^{2} - { \tan(x) }^{2} = 1$
${ \sec(x) }^{2} - {(3 \div 4)}^{2} = 1$
${ \sec(x) }^{2} - (9 \div 16) = 1$
${ \sec(x) }^{2} = 1 + 9 \div 16$
${ \sec(x) }^{2} = 25 \div 16$
sec x = 5/4

cos x = 1/sec x = 4/5

Answer 2

heya ____________________________________

here is your ans

→ refer to the attachment

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