Question

if tan thita= 3/4, then find sec thita and cos thita​

Answer 1

tan thita=3/4 and tan thita=p/b

then using PGT theorem

base^2+perpendicular^2=hypotenuse^2

4^2+3^2=ac^2

16+9=Ac^2

25=Ac^2

5=AC

sec thita=h/b=5/4

cos thita=b/h=4/5

Answer 2

Answer :

• $sec \theta = \frac{5}{4}$
• $Cos \theta = \frac{4}{5}$

Solution :

Value of tanθ is given 3/4. we know that tanθ = p/b . it's means that Perpendicular is 3 and base is 4. Now, we can find the value of hypotenuse using Pythagoras theorem :-

$\red\bigstar\:\boxed{\sf H^2 = P^2+B^2 }$

Putting the values,

h² = b²+p²

h² = 3²+4²

h²= 25

h= 5

so,

• secθ = h/b=5/4

• cos thita=b/h=4/5