Question

If tan thita= -3/5, then sin thita is ?​

Answer 1

Step-by-step explanation:

Let theta = x

tan x=1/2 = prep(AB)/base(BC)

Let in right angled triangle B=90° ,prep.(AB) =k unit. then base (BC)= 2k units.

AC^2=AB^2+BC^2

AC^2= k^2 + 4k^2=5k^2

AC (hypotenuse) =k.√5.units

sin x= prep.(AB)/hypo.(AC)

sin x=k units/k.√5.units.

sin x= 1/√5 . , Answer.

Answer 2

Answer:

$\huge\star\underline{\orange{❥︎a}\mathfrak\blue{n}\mathfrak\purple{S}\mathbb\pink{wer}}\star\:$

b. tanθ=3−4

⇒θ∈ II quadrant or  IV quadrant 

⇒sinθ=±4/5

 If θ∈II quadrant, sinθ=4/5

 If θ∈IV quadrant, sinθ=−4/5

@Hᥱr⳽ᖾᥱყsKᎥ⳽⳽ᥱ⳽⳽ ♡