If tan thita =cot thita then value of sec thita
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If tan θ=cot θ...(1)
So,
tan θ = 1
tan θ
tan²θ = 1 ...(2)
and
sec²θ = 1 .....(3)
cos²θ
We know that sin² θ + cos² θ =1
Look at the picture
sin² θ + cos² θ = 1
(y)²+(x)² = 1
(r) (r)
y²+x² = 1
r² r²
y²+x² = 1
r²
r² = 1
r²
1 = 1
So ,next
⇒tan² θ = sin² θ+cos² θ
⇒sin² θ = sin² θ + cos² θ
cos² θ
⇒ 1 = sin²θ + cos²θ
cos²θ sin²θ
⇒ 1 = 1 + cos²θ⇔input equation 3
cos²θ sin²θ
⇒sec² θ = 1+cot² θ⇔input equation 1
⇒sec²θ = 1 +tan²⇔input equation 2
⇒sec² θ = 1+1
sec² θ = 2
secθ =√2
-----------------------------------------SOLVED----------------------------------------------
So,
tan θ = 1
tan θ
tan²θ = 1 ...(2)
and
sec²θ = 1 .....(3)
cos²θ
We know that sin² θ + cos² θ =1
Look at the picture
sin² θ + cos² θ = 1
(y)²+(x)² = 1
(r) (r)
y²+x² = 1
r² r²
y²+x² = 1
r²
r² = 1
r²
1 = 1
So ,next
⇒tan² θ = sin² θ+cos² θ
⇒sin² θ = sin² θ + cos² θ
cos² θ
⇒ 1 = sin²θ + cos²θ
cos²θ sin²θ
⇒ 1 = 1 + cos²θ⇔input equation 3
cos²θ sin²θ
⇒sec² θ = 1+cot² θ⇔input equation 1
⇒sec²θ = 1 +tan²⇔input equation 2
⇒sec² θ = 1+1
sec² θ = 2
secθ =√2
-----------------------------------------SOLVED----------------------------------------------
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