if tan thita +sec thita = e^x then cos thuta =
Answers
Answered by
0
tanθ+secθ=e
x
⇒
cosθ
1+sinθ
=e
x
⇒
cos
2
θ
−sin
2
θ
cos
2
θ
+sin
2
θ
=e
x
(U\sin g componendo & Dividendo rule)
⇒tan
2
θ
=
e
x
+1
e
x
−1
as cosθ=
1+tan
2
2
θ
1−tan
2
2
θ
⇒cosθ=
1+(
e
x
+1
e
x
−1
)
2
1−(
e
x
+1
e
x
−1
)
2
⇒cosθ=
e
2x
+1
2e
x
⇒cosθ=
e
x
+e
−x
2
.
OPTION B
Similar questions